Permutated Pooled Pascal (Power of 6)

Algebra Level 3

( 1 + 2 + 3 + 4 + 5 + 6 ) 1 + 6 ( 1 + 2 + 3 + 4 + 5 ) 2 + 15 ( 1 + 2 + 3 + 4 ) 3 + 20 ( 1 + 2 + 3 ) 4 + 15 ( 1 + 2 ) 5 + 6 ( 1 ) 6 = ? \begin{aligned} & & { (1+2+3+4+5+6) }^{ 1 } \\ & + & 6{ (1+2+3+4+5) }^{ 2 } \\ & + & 15{ (1+2+3+4) }^{ 3 } \\ & + & 20{ (1+2+3) }^{ 4 } \\ & + & 15{ (1+2) }^{ 5 } \\ & + & 6{ (1) }^{ 6 } \\ & = & ? \\ & & \end{aligned}


The answer is 45942.

Abyoso Hapsoro by Abyoso Hapsoro , 22, Indonesia

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2 solutions

Vaibhav Chandan
May 26, 2015

Could'nt see any shorter way than adding them up!!!!!!!!

1 Helpful 0 Interesting 0 Brilliant 0 Confused
Rama Devi
May 14, 2015

I couldn't find more easier method than adding all of them , which gives the answer as 45942.

1 Helpful 0 Interesting 0 Brilliant 0 Confused

Lol, so do i

yessy yosephine - 6 years ago

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