Permutation

Probability Level 2

A restaurant offer 5 choices of appetizer, 10 choices of main meal, and 4 choices of dessert. A customer can choose to eat just one course or two different courses, or all three courses. Assuming all three choices are available, how many different possible meals does the restaurant offer?


The answer is 329.

John Andee Legaspi by John Andee Legaspi , 25, Philippines

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2 solutions

Samiur Rahman Mir
Oct 22, 2014

one course- 5 + 10 + 4 = 19 5+10+4=19

two courses - 5 × 10 + 10 × 4 + 5 × 4 = 110 5 \times 10 + 10 \times 4 + 5 \times 4=110

three courses - 5 × 10 × 4 = 200 5 \times 10 \times 4=200

Total 329 329

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Vishnu Prasad
Dec 25, 2014

The course chosen can be divided as follows: Any of of total choices i.e 19C1 =19 Any of 2 taken at a time i.e (5C1) (10C1)+(10C1) (4C1)+(4C1) (5C1)=50+40+20=110 All Three at once : (4C1) (5C1)*(10C1)=200 Total=200+110+19=329 choices.

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