How many intergers are there betwen 100 and 1000 that contains only one 7?
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first we consider the number _ _ 7
without 7 we can choose the first gap is 8 and second gap is 9
the possible value is = 8 ∗ 9 = 7 2
now we consider the number _ 7 _
without 7 we can choose the first gap is 8 and third gap is 9
the possible value is = 8 ∗ 9 = 7 2
last we consider the number 7 _ _
without 7 we can choose the second gap is 9 and third gap is 9
the possible value is = 9 ∗ 9 = 8 1
so 2 ∗ 7 2 + 8 1 = 2 2 5