permutations

Probability Level pending

the number of ways of arranging the letters of the word "SUPER" such that the vowels are always surrounded by at least one consonent is


The answer is 108.

Sudoku Subbu by sudoku subbu , 19, India

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Sudoku Subbu
Jan 16, 2015

the total ways of arranging the letters of the word "SUPER" is 5! = 120 . the no. of ways such that the vowels does not have a consonent is 3! + 3! = 6 + 6 = 12 total no. of ways of arrangin g = 120 - 12 = 108

0 Helpful 0 Interesting 0 Brilliant 0 Confused

But there are two vowels and we got to corners ..so the ans should be .. 5! - ( 3! 2! 2)=96 Please tell where did i made mistake?

Anurag Pandey - 6 years, 1 month ago

Log in to reply

first understand man! total ways=120 the case where vowels are not surrounded by atleast 1 consonent is "UE_ _ "and" _ _UE" so in both cases the 3 dashes can be filled with the letters S,P,R in 3! ways> so you have to subract 3!+3!=6+6=12 from 120=> 120-12=108 nice doubt man thanks visit my other problems it will be interesting bye?!?!

sudoku subbu - 6 years ago

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...