Permute it!

The number of permutations of the set { 1 , 2 , 3 , 4 } \{1,2,3,4\} in which no two adjacent positions are filled by consecutive integers (increasing order) is :

13 11 17 19

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1 solution

No. Of permutations using Principle of Inclusion & Exclusion is:

4 ! 3 × 3 ! + 3 × 2 ! 1 ! = 11 4!-3\times 3!+3\times 2!-1!=11

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