Peter vs Tire

Peter puts a board on top of a tire, as shown. He pushes the board so that the tire rolls without slipping. If the tire moves by a distance of 2 m 2 \text{ m} , what is the distance Peter moves?

1 m 1 \text{ m} 2 m 2 \text{ m} 3 m 3 \text{ m} 4 m 4 \text{ m}

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1 solution

Consider the final position of the initial point of contact of the board with the tire. The tire will travel the same distance d d as the length of board it comes into contact with, so the initial point of contact will be a distance d d ahead of the final point of contact, i.e., the initial point of contact will have travelled a total distance of 2 d 2d . Since Peter maintains a constant distance from the board's initial point of contact, he too will have travelled a distance of 2 d 2d , which in this instance is 2 × 2 = 4 2 \times 2 = \boxed{4} m.

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