Peter's Game

Algebra Level 1

In a game, Peter rolls five normal dice. What is the probability that no sixes are rolled.

Note : Your answer will be accepted as a decimal value, not a percentage or fraction.


The answer is 0.402.

Surayyah Aziz by Surayyah Aziz , 18, United Kingdom

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

2 solutions

X X
Aug 4, 2018

P = Rolling 5 times and get no sixes Rolling 5 times = 5 5 6 5 ≈ 0.402 P=\dfrac{\text{Rolling 5 times and get no sixes}}{\text{Rolling 5 times}}=\dfrac{5^5}{6^5}\approx 0.402

0 Helpful 0 Interesting 0 Brilliant 0 Confused
Surayyah Aziz
Aug 4, 2018

Solution: ( 5 6 \frac{5}{6} )^5 = 0.402

0 Helpful 0 Interesting 0 Brilliant 0 Confused

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...