Let an integer α be called awkward, if φ(α)D(α)⩽α^2-[αD(α)/2], where φ(α) is no of naturals x co-prime to α, x⩽α, D(α) be the no of divisors of α. Let A={x | x is an awkward number}, and let a<b<c<d<e ... be the list of such awkward numbers. If p = (a + b + c + d + e)/(3(a+b)+2), find [((p^3 + p^2 -1)^12)/1000], where [x] is its floor function.
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