Petty Problem's Double Trouble

Logic Level 2

Henry is confused by a petty problem.

A , A , B , C , E , H , M , U , ? , C \large A, A, B, C, E, H, M, U, ?, C

What is the ? ?

L H V S D W X C

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2 solutions

Matin Naseri
Aug 18, 2018

Fibonacci numbers as letters.

Note: we have only 26 letters in English thus then 34 26 = 8 ; 8 = H 34-26= 8; 8= {\boxed{H}}

Yeah! That's correct

Mohammad Farhat - 2 years, 9 months ago

Instead of subtracting, it would be better to use mod 26 than subtracting 26 because what if I gave a bigger number like 200 then instead of subtracting until the difference is lower than 26. Easily the representation is correct and it is not laborious. Still, Nice answer. Sweet and concise

Mohammad Farhat - 2 years, 9 months ago
Mohammad Farhat
Aug 17, 2018

This is actually an easy problem but I disguised it.

You see, I actually made this a part of the Fibonacci sequence involving letters.

1 , 1 , 2 , 3 , 5 , 8 , 13 , 21 , 34 \huge 1,1,2,3,5,8,13,21,34 …

An then according to the alphabet I coded it with numbers and Voila.

1 , 1 , 2 , 3 , 5 , 8 , 13 , 21 , 34 \large 1, 1, 2, 3, 5, 8, 13, 21, 34 …

A , A , B , C , E , H , M , U , H \large A, A, B, C, E, H, M, U, H …

I was trying to match them. Sorry.

You may be surprised and you might say, "Since when was H the 34th letter of the alphabet. Well It is the 34th letter mod 26. And since 34 8 34 \equiv 8 (mod 26) then we take the eighth letter which is H \boxed{H} .

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