Photoelectric Effect

In a photo-emissive cell, when light of wavelength λ \lambda is incident, the maximum kinetic energy of electron is K K . When incident light of wavelength 3 λ 4 \frac{3\lambda}{4} is incident on the same photo-emissive cell, the maximum kinetic energy of an electron will be :

greater than 4 K 3 \frac{4K}{3} 3 K 4 \frac{3K}{4} less than 4 K 3 \frac{4K}{3} 4 K 3 \frac{4K}{3}

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1 solution

Raushan Sharma
Jun 3, 2016

Let the Work Function of the surface of the photo-emissive cell be W W .

By Einstein's equation of Photo-electricity, we have:

h c λ = W + K \frac{hc}{\lambda} = W + K , where K K is the max. K.E when light of wavelength λ \lambda is incident on it

h c λ > K \Rightarrow \frac{hc}{\lambda}> K , since W > 0 W >0

And, when light of wavelength 3 λ 4 \frac{3\lambda}{4} is incident on the same surface, we have:

4 h c 3 λ = W + K \frac{4hc}{3\lambda} = W + K' , where K K' is the max. K.E when light of wavelength 3 λ 4 \frac{3\lambda}{4} is incident on it

Subtracting the two equations, we get: K = h c 3 λ + K > K 3 + K = 4 K 3 K' = \frac{hc}{3\lambda} + K > \frac{K}{3} + K = \frac{4K}{3}

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