Physic lovers....

Level 2

A cricketer can throw a ball max. Horizontal to a distance of 100m. How much high above can the cricketer throw the same ball???


The answer is 50.

Kundan Rathi by Kundan Rathi , 17, India

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2 solutions

Lakshya Khilwani
Oct 8, 2018

We know Horizontal. Distance = U 2 g \frac{U^2}{g}

100 = U 2 g \frac{U^2}{g}

U²= 100g

We also know vertical maximum height = U 2 2 g \frac{U^2}{2g}

Substituting the values

Vertical Maximum Height = 100 g 2 g \frac{100g}{2g}

= 50 m

1 Helpful 0 Interesting 0 Brilliant 0 Confused
Kundan Rathi
Oct 5, 2018

R=u²/g

U²=100g

U=√100g

V=0

By v²-u²=2as

-100g=-2gs

S=-100g/-2g

=50m

0 Helpful 0 Interesting 0 Brilliant 0 Confused

Why can't you use latex so that others will appreciate your solution.

Ram Mohith - 2 years, 8 months ago

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