If a ball is projected horizontally at 60 degrees , and the time to reach the ground is 20 Seconds than Find the vertical height Covered by the ball in that time ( in metres) Also take g = 10 m/s2 .
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We know that at the maximum height, at half the time, the velocity in the y direction would be zero.
V i y − 2 g t =0
Plugging in the values of g and half t, 10 and 10 respectively, we get V i y = 1 0 0 m / s .
We know that the velocity in the vertical direction at any point in time is given by the function
V y ( t ) = 1 0 0 − 1 0 t
Integrating this from time 0 to 10, we get the distance 500 metres.