Physics' concept - 5

Classical Mechanics Level 3

A person attaches an electronic weighing machine on his feet and jumps from a high mountain on earth (I don't know why) .While falling , he sees that his weighing machine reads his weight as ' $a$ ' kilograms. The same person (alive, I don't know how) then performs the same experiment on the moon and while falling his weighing machine reads his weight as ' $b$ ' kilograms.

Find the value of $\dfrac{a}{b}$ .

6 0 Undefined

\dfrac{1}{6}

3 solutions

Nihar Mahajan
May 20, 2015

A weighing machine measures the normal force that the earth exerts on a body when the body is placed on its surface. Since the person was in the air , there is no force from the earth and thus the reading shows 0 .Same in case of moon and the reading shows 0. Thus answer is $\dfrac{0}{0}$ which is undefined.

I didn't see the "b" part. :3 Easy problem, though.

Mehul Arora - 6 years ago

Sir, you were certainly right about your comment on " Are you clear with L.C.M.?" posted by Naitik Sanghavi. I didn' t know that earlier. Thank you so much for sharing that idea.

http://math.stackexchange.com/questions/44836/rational-numbers-lcm-and-hcf This link is also telling the same thing and process that you had mentioned. But, I have one question. Why Wikepedia is telling that GCD & LCM are only valid for integers? Maybe, I am wrong this time also. But, please clarify the concept about this GCD & LCM. Are these two only valid for INTEGERS & RATIONAL NUMBERS ?

Rubayet Tusher - 6 years ago

LCM , GCD can be calculated for all rational numbers as stated in the link you gave above. If you see the 3.1 section of wikipedia , at the last of this section , they have given an example of rational numbers.

Nihar Mahajan - 6 years ago

Thank you Sir for your kind reply. I've checked that section.

Rubayet Tusher - 6 years ago

I just saw "a" and then 0 :(....

Samarth Agarwal - 6 years ago

This question seems to be easy.But the problem should be visualize first properly.Then better to solve this.

Rafhan Rafhan - 5 years, 11 months ago

Wait thats so cheap I was thinking of equal acceleration theory and all that junk wth

CS ಠ_ಠ Lee - 6 years ago

Harvindersingh Chavan
May 21, 2015

Very good question... i first thought answer to be 6. Then i read again and since he was in freefall, his weight in both cases would be zero because of absence of normal reaction. $\frac {0}{0}$ = Not Defined.

Saaket Sharma
May 22, 2015

yup .....we all fall freely under action of gravitational force....So ans-0/0

Physics' concept - 5

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