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Classical Mechanics
Level
2
A particle of mass 5 kg is at limiting equilibrium on a rough plane which is inclined at an angle of 30 degrees to the horizontal. Find the coefficient of friction between the particle and the plane.
0.433(3sf)
0.577 (3sf)
0.463(3sf)
0.567(3sf)
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1 solution
Resolving up the plane: F - 5gsin30 = 0
Resolving perpendicular to the plane: R = 5gcos30
In limiting equilibrium, so F = mR 5gsin30 = m5gcos30
m = sin30/cos30 = 0.577 (3sf)
hope it helped you !