The equation for displacement is x = 9t² + 7t. If a block covers a distance of 24m over a certain period of time. And a force is being applied on the block over an area of 27m² .Assumping that block is of 3kg .
Find the 5(magnitude of pressure + magnitude of force + magnitude of acceleration )
Assumptions and details
My Inspiration Aryan Sanghi
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
s = 9 t ² + 7 t
a = d t ² d ² s
a = 1 8 m / s ²
F = m a F = 5 4 N
P = A F P = 2 P a
A n s w e r = 5 ( a + F + P ) A n s w e r = 5 × 7 4 A n s w e r = 3 7 0
Same method!
Problem Loading...
Note Loading...
Set Loading...
the displacement equation is of the form d = v i t + 2 a t 2 the displacement equation is 7 t + 2 1 8 t 2 , therefore the acceleration is 18m/s 2 . Or you could differentiate the displacement equation two times with respect to t . Either way works. The force is given by Newton's second law, F = m a , in this case F = 1 8 ∗ 3 =54 Newtons. The pressure is given by the equation P = A r e a F o r c e .
Plugging in the values, we get pressure=2 pascals Plugging the values of pressure, force, and area into the answer 5 ( a + F + P ) , the answer is 370