Keys on the table!

Assume there are 20 20 keys on a table, 10 10 are white, and 10 10 are black (Every key of the same color are indistinguishable).

(A) How many ways can the 20 keys be arranged? Rotations and reflections are counted.

(B) If 2 2 keys are randomly picked, what is the probability of 1 being white and the other black? (If the probability is m n \frac{m}{n} , (B) would be m + n m+n ).

(C) Is (A) prime? (If answer is yes, (C) would be 3 3 , If answer is no, (C) would be 2 2 ).

(D) Is (B) prime? (If answer is yes, (D) would be 3 3 , If answer is no, (D) would be 2 2 ).

(E) Is (C) prime? (If answer is yes, (E) would be 3 3 , If answer is no, (E) would be 2 2 ).

And finally:

(F) What is A+B+C+D+E?


The answer is 184791.

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1 solution

Micah Gadbois
Jul 18, 2017

(A): 2 19 2^{19} = = 524288 524288 ( 2 2 ways for first key, 2 2 ways for second key, . . . . . ) .....)

(B): There are 20 C 2 20C2 = = 190 190 ways to choose 2 2 keys. There are 100 100 ways to pick 1 1 white and 1 1 black key. 100 190 \frac{100}{190} = = 10 19 \frac{10}{19} . Thus, 10 + 19 10+19 = = 29 29

(C): (A) is not prime, so answer is 2 2

(D): (B) is prime, so answer is 3 3

(E): (C) is prime, so answer is 3 3

(F): 524288 + 29 + 2 + 3 + 3 524288+29+2+3+3 = = 524325 524325

Edit: This is incorrect. Look at other Solution

In general, avoid making your questions as "take this number and do a bunch of stuff to it". Instead, it would be better to allow people to focus on the crux of your problem directly.


A lot of your answers are wrong.

A = ( 20 10 ) = 184756 A = { 20 \choose 10} = 184756 ,
B = 1 2 3 B = \frac{1}{2} \rightarrow 3 ,
C - no - 2
D - yes - 3
E - yes (always prime) - 3
F - 184767


I have updated the answer accordingly.

Calvin Lin Staff - 3 years, 10 months ago

That's not correct. In part B, the probability to pick any color is 1. There are 10 of the other color, and 19 left, so B is 10/19. 10+19 = 29

Micah Gadbois - 3 years, 10 months ago

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Alright, let me run the calculations.

Given such an arrangement, there are 10 × 9 × 2 10 \times 9 \times 2 ways that we can pick 2 ordered keys with different colors. There are 20 × 19 20 \times 19 ways to pick 2 ordered keys. Hence, the probability is 9 19 \frac{ 9}{19} .

So this gives us B = 28, D = 2. I have updated the answer to 184791.

Calvin Lin Staff - 3 years, 10 months ago

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