Assume there are keys on a table, are white, and are black (Every key of the same color are indistinguishable).
(A) How many ways can the 20 keys be arranged? Rotations and reflections are counted.
(B) If keys are randomly picked, what is the probability of 1 being white and the other black? (If the probability is , (B) would be ).
(C) Is (A) prime? (If answer is yes, (C) would be , If answer is no, (C) would be ).
(D) Is (B) prime? (If answer is yes, (D) would be , If answer is no, (D) would be ).
(E) Is (C) prime? (If answer is yes, (E) would be , If answer is no, (E) would be ).
And finally:
(F) What is A+B+C+D+E?
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(A): 2 1 9 = 5 2 4 2 8 8 ( 2 ways for first key, 2 ways for second key, . . . . . )
(B): There are 2 0 C 2 = 1 9 0 ways to choose 2 keys. There are 1 0 0 ways to pick 1 white and 1 black key. 1 9 0 1 0 0 = 1 9 1 0 . Thus, 1 0 + 1 9 = 2 9
(C): (A) is not prime, so answer is 2
(D): (B) is prime, so answer is 3
(E): (C) is prime, so answer is 3
(F): 5 2 4 2 8 8 + 2 9 + 2 + 3 + 3 = 5 2 4 3 2 5
Edit: This is incorrect. Look at other Solution