Pieces of a Mystery Line

Geometry Level 2

Consider two lines 9 x + 4 y + 1 = 0 , 4 x + 15 y + 16 = 0. 9x+4y+1=0, \hspace{.5cm} 4x+15y+16=0. If a third line y = m x + b y=mx+b has the same slope as the first line and passes through the x x -intercept of the second line, what is b m \frac{b}{m} ?


The answer is 4.

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1 solution

Andrew Ellinor
Sep 28, 2015

We rewrite the equation of the first line to obtain 9 x + 4 y + 1 = 0 y = 9 4 x 1 4 m = 9 4 . 9x+4y+1=0 \Rightarrow y=-\frac{9}{4}x-\frac{1}{4} \Rightarrow m=-\frac{9}{4}.

To obtain the x x -intercept of the second line, we substitute y = 0 y=0 and solve for x x : 4 x + 15 0 + 16 = 0 x = 4. 4x+15\cdot 0+16=0 \Rightarrow x=-4. This implies that the third line y = m x + b = 9 4 x + b y=mx+b=-\frac{9}{4}x+b passes through point ( 4 , 0 ) (-4, 0) . Thus, we substitute x = 4 x=-4 and y = 0 y=0 to obtain 0 = 9 4 ( 4 ) + b b = 9 b m = ( 9 ) ( 4 9 ) = 4. \begin{aligned} 0=-\frac{9}{4} \cdot (-4)+b &\Rightarrow b=-9 \\ &\Rightarrow \frac{b}{m}=(-9) \cdot \left(-\frac{4}{9}\right) =4. \end{aligned}

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