Pigeonhole principle practice problem 1

A Professor tells 3 Jokes in his ethics class each year.How large a set of jokes does the professor need in order never to repeat the exact same triple of jokes over a period of 12 years?


The answer is 6.

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1 solution

We need to find the least positive integer n n such that ( n 3 ) 12. \dbinom{n}{3} \ge 12.

Now f ( n ) = ( n 3 ) f(n) = \dbinom{n}{3} is an increasing function for integers k 3. k \ge 3. So since f ( 5 ) = 10 f(5) = 10 and f ( 6 ) = 20 f(6) = 20 we can conclude that the professor needs at least 6 \boxed{6} jokes to choose from.

The problem I have with this question is the use of the word "triple". Usually triple is taken to mean that it is a permutation which gives 4 3 2>12, so the answer would be 4. A better wording would be "so that he doesn't tell the same set of 3 jokes in 12 years"

Brennan Ravan - 3 years ago

yeah it should have been so that he doesn't tell the same set of 3 jokes in 12 years

shlok panch - 2 weeks ago

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