Ping-Pong Cells

Probability Level pending

I am an n n -dimensional creature ( n > 2 ) (n>2) working at a ping-pong ball factory. Today, I made a collection of ping-pong balls of the following form: the first was a 1-dimensional line with side length one, the second was a 2-dimensional triangle with side length two, the third was a 3-dimensional tetrahedron with side length three, and so on. I made figures up to an n + 1 n+1 -cell with side length n + 1 n+1 , then counted all the balls in all the figures. It turned out that the number of balls totaled a square integer! What is the smallest dimension n n that I could live in?


The answer is 4.

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1 solution

Cedar Turek
Oct 16, 2018

An n-cell is a figure in n-1 dimensions that connects n points, each in a new dimension, to each other. The formula for finding the total number of balls in an n-cell with side length x is ( x ) ( x + 1 ) ( x + 2 ) ( x + 3 ) ( x + n 1 ) n ! \frac{(x)(x+1)(x+2)(x+3)\ldots(x+n-1)}{n!} . The "line" will be made up of one ball, the triangle will be made up of ( 2 ) ( 3 ) 2 = 3 \frac{(2)(3)}{2}=3 balls, and the tetrahedron will be made up of ( 3 ) ( 4 ) ( 5 ) 3 ! = 10 \frac{(3)(4)(5)}{3!}=10 balls. The next figure, a 5-cell, will contain ( 4 ) ( 5 ) ( 6 ) ( 7 ) 4 ! = 35 \frac{(4)(5)(6)(7)}{4!}=35 balls. At this point, the total is 49, which is a perfect square. Thus, the answer is four.

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