Pipa.

Algebra Level 3

A pipe A can fill a tank in 2/3 the time that can pipe B can fill it in 4/5 the time that pipe C can. And the pipe A and C can fill it in 8 hours. How long required to fill the tank with all pipes working together?

[This question is not clearly phrased.]


The answer is 5.5757.

Jade Lendel by Jade Lendel , 24, Philippines

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1 solution

a+c=1/8 a=2/3 b b=4/5 c b=(1/8)*(12/23) a+b+c=? Using the value of b and change the other variables to b in the above equation, we will get a+b+c=4.375/23 then after taking inverse 1/(a+b+c)=5.26

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Need a clarification going by the ratio Work contribution A:B IS 3:2 and B: C IS 5;4 i.e A:B:C work contribution ratio is 15:10:8 Therefore time taken when A B C work together is 23/33 of original time of 8 hours. i.e 5.575 hours. Why am I getting a different answer?

Vivek Bakshi - 7 years, 2 months ago

ans is 5.575 ,what wrong rajarajan is doing is (1/a+1/c)'rate of work=1/8 is rate of work of a & c ,and a'time=2/3 of b's time , b's time=4/5 of c'time,is ratio of time given,and time is inverse of rate of work. sol is b=4/5c, so i/c=4/(5b),& 1/a=3/(2b),1/b=10/184 (1/a + 1/b + 1/c) time=1 (3/2 +4/5+ 1) 1/b *time=1 time=184/33=5.57

AVINASH chandra - 7 years, 2 months ago

exact answer is = 23 * 8 / 33 = 5.575

Raj Gupta - 7 years, 2 months ago

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