Five pirates stole 1000 gold bars. They want to divide the loot between each other. They find out the following:
The fisrt pirate finds out a way of dividing. Then each pirate desides that if this method is good for him. If minimum half of the pirates like the idea, then they divide the bars with the first pirate's method. In the other case they kill the pirate, and the second has to find out a way of dividing. Then each pirate desides that if this method is good for him. If minimum half of the pirates like the idea, then they divide the bars with the second pirate's method. In the other case the second pirate dies and the third has to find out a way of dividing...and so on
Maximum how many gold bars can the first pirate get?
Note: Each pirate is very clever, and very greedy. They can't divide the bars.
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
The first pirate wants at least two other pirates to be happy, se 3 of the 5 pirates are happy. The two other pirates each get a gold bar. 1000-2=998.