Pizza Cutting Puzzle!

Geometry Level 5

A 12 inch diameter round pizza

has been sliced by 3 straight cuts, leaving a right triangle in the middle as shown here

The edge of the pizza has been cut into 6 arcs, one each of the following, in degrees, totaling 360 degrees:

15 , 30 , 45 , 60 , 90 , 120 {15, 30, 45, 60, 90, 120}

but not necessarily in that order. The maximum area, in square inches, this right triangle piece in the middle can have can be expressed as

1 a ( b + c 2 + d 3 + e 6 ) \dfrac { 1 }{ a } (b+c\sqrt { 2 } +d\sqrt { 3 } +e\sqrt { 6 } )

where a , b , c , d , e a, b, c, d, e are integers (which may be negative). Find a + b + c + d + e a+b+c+d+e .

Integer a a is positive. Do not rely on diagram to guess arcs in degrees.


The answer is 58.

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1 solution

Michael Mendrin
Jul 11, 2014

The exact maximum area is

1 4 ( 72 45 2 + 60 3 33 6 ) \dfrac { 1 }{ 4 } (72-45\sqrt { 2 } +60\sqrt { 3 } -33\sqrt { 6 } )

obtained by cutting the pizza into arcs in the following order

30 , 45 , 60 , 90 , 15 , 120 30,45,60,90,15,120

Hence, 4 + 72 45 + 60 33 = 58 4+72-45+60-33=58

To simplify search for maximum right triangle, note that 2 2 perpendicular chords in a circle divide the edge into 4 4 arcs such that opposite arcs always add up to 180 180 degrees. Then you could almost infer the optimum order of arcs by sketching on paper.

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