Pizza offer!

We show that: $2A_{8} < A_{12}$ and so you should not accept the offer

\[\begin{align} 2 A_{8} &= 2 \left( \dfrac{\pi (8)^2}{4} \right) \\ &= 2(16 \pi) \\ &= 32 \pi \end{align}

\quad \quad \quad

\begin{align} A_{12} &= \left( \dfrac{\pi (12)^2}{4} \right) \\ &= 144/4 \pi \\ &= 36 \pi \end{align}\]

$\boxed{ 2A_{8} < A_{12}}$

You might be tempted to go for the offer. But if you think mathematically you will not. The radius of the 12 inch pizza is 6 inches. So the area would be 36 $\pi$ . In the case of the offer, the radius of each pizza would be 4 inches, which means area of two pizza's would be 32 $\pi$ . Obviously 36 $\pi$ is greater than 32 $\pi$ . So accepting the offer is not the best idea.