Play around with numbers

How many ordered pairs ( A , B ) \left(\color{#D61F06}{A,B}\right) exist so that the number 21 A 53 B 4 \color{#3D99F6}{21}\color{#D61F06}{A}\color{#3D99F6}{53}\color{#D61F06}{B}\color{#3D99F6}{4} is divisible by 44?

Note: A , B \color{#D61F06}{A,B} are single digit whole numbers.

More than 4 3 4 2 1

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1 solution

Dev Sharma
Oct 28, 2015

21 A 53 B 4 21A53B4 is divisible by 44. It means its divisible by 11 and 4 too.

Applying divisibility rule of 11,

( A + 9 ) ( 6 + B ) = 0 m o d 11 (A + 9) - (6 + B) = 0 mod11

A B + 3 = 0 m o d 11 A - B + 3 = 0 mod11

Applying divisibility rule of 4, we find that B can be 0, 2, 4, 6, or 8.

Putting all these in equation above give the following pairs only :

(1,4),(3,6),(5,8),(8,0)

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