Play With Roots Of Equation

Calculus Level 3

If a + b + c = 0 a+b+c=0 , then which of the following must be true regarding the quadratic equation 3 a x 2 + 2 b x + c = 0 3ax^2 +2bx+c=0 ?

It has one root in ( 2 , 3 ) (2,3) and other in ( 2 , 1 ) (-2,-1) It has at least one root in the interval ( 0 , 1 ) (0,1) It has imaginary roots Can't be determined None of the above

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1 solution

Rishi Sharma
May 17, 2016

Relevant wiki: Rolle's Theorem

C o n s i d e r f ( x ) = a x 3 + b x 2 + c x , A s t h i s i s a p o l y n o m i a l f u n c t i o n i t i s c o n t i n o u s a n d d i f f e r e n t i a b l e i n . ( i s t h e s e t o f a l l r e a l n u m b e r s ) N o w w e n o t i c e t h a t f ( 0 ) = f ( 1 ) = 0 ( a + b + c = 0 ) S o b y a p p l y i n g R o l l e s T h e o r e m i n t h e i n t e r v a l ( 0 , 1 ) w e c a n s a y t h a t d d x ( f ( x ) ) w i l l h a v e a t l e a s t o n e z e r o i n ( 0 , 1 ) o r 3 a x 2 + 2 b x + c w i l l h a v e a t l e a s t o n e z e r o i n ( 0 , 1 ) \\ Consider\quad f\left( x \right) =a{ x }^{ 3 }+b{ x }^{ 2 }+cx,\quad As\quad this\quad is\quad a\quad polynomial\quad function\\ it\quad is\quad continous\quad and\quad differentiable\quad in\quad \Re .\quad (\Re \quad is\quad the\quad set\quad of\quad all\quad real\quad numbers)\\ Now\quad we\quad notice\quad that\quad f\left( 0 \right) =f\left( 1 \right) =0\quad (\because \quad a+b+c=0)\\ So\quad by\quad applying\quad \quad Rolle's\quad Theorem\quad in\quad the\quad interval\quad (0,1)\quad we\quad can\quad say\quad that\\ \frac { d }{ dx } (f\left( x \right) )\quad will\quad have\quad atleast\quad one\quad zero\quad in\quad (0,1)\\ or\quad 3a{ x }^{ 2 }+2bx+c\quad will\quad have\quad atleast\quad one\quad zero\quad in\quad (0,1)

interesting, but can you find the root ???

Frank Giordano - 4 years, 9 months ago

if we let b=-2c, then a=c and we have, assuming c not equal to zero, the factored form c(3x-1)(x-1) which has root x=1/3 inside the interval (0,1).

Frank Giordano - 4 years, 9 months ago

i used G-filtered Polycules to POINT to the solution, FYI https://www.facebook.com/groups/factorthis/

Frank Giordano - 4 years, 9 months ago

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