Playing with Powers of 2

Let P ( x ) P\left( x \right) be the sum of the digits of x x . We define T ( x ) T\left( x\right) as applying P ( x ) P\left( x \right) to the number x x , and then to the result (repeatedly), until the outcome is a single digit. For example, T ( 249 ) : P ( 249 ) = 15 , P ( 15 ) = 6 T\left( 249 \right) :\quad P(249)=15,\quad P(15)=6 so T ( 249 ) = 6 T\left( 249 \right) =6 .

Let T ( 2 2016 ) = N T({ 2 }^{ 2016 })=N . Find the least possible value for x > 1 x>1 that satisfy 2 P ( x ) N ( m o d x ) { 2 }^{ P(x) }\equiv N \pmod x .


The answer is 17.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...