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1 6 1 5 − 8 1 5 − 4 1 5 − 2 1 5 − 1 1 5 Can be written after factorising as
1 6 1 5 - [ 2 1 5 + 1 ].[ 2 3 0 + 1 ].. Eq1
Let 2 1 5 + 1 be a
Let 2 3 0 + 1 be b
a is congruent to 33 mod 96
b is congruent to 65 mod 96
a b is congruent to 33 mod 96 .
And 1 6 1 5 is congruent to 64 mod 96
So when Eq1 is checked mod 96 then 64-33= 31 is the answer.