Pointing to the Poynting!

Find the mean Poynting vector of a plane electromagnetic wave E = E m c o s ( ω t kr ) \textbf{E} = {\textbf{E}}_{m}cos(\omega t - \textbf{k}\textbf{r}) if the wave propagates in vacuum.

If the answer can be written as

S a v = a b μ 0 c E m d k e ω f \displaystyle {S}_{av} = \frac{a}{b} {{\mu}_{0}}^{c}{{\textbf{E}}_{m}}^{d}{\textbf{k}}^{e}{\omega}^{f}

where a , b , c , d , e a,b,c,d,e are positive reals.

Give your answer as a + b + c + d + e + f \displaystyle a + b + c + d + e + f


The answer is 4.

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1 solution

Vishnu C
Jun 27, 2015

S a v = E m 2 2 μ 0 c S_{av} = \frac {E_m^2} {2\mu_0c} and c = ω k c = \frac \omega k

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