Points Q and R are on segment PS, which has length 24. If PQ is half as long as QS, and QR is 3 times as long as RS, how long is RS?
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PS = PQ+QR+RS = 24, substitute QR with 3RS, PQ +4RS = 24, from PQ = QS/2, PQ =( QR + RS)/2, PQ = (3RS +RS)/2, PQ = 2RS therefore PS = 2RS = 4RS = 24, simplify: RS = 4
PQ+QR+RS = 24
Substituting the given values in terms of RS (the required distance),
0.5(3RS+RS) + 3RS + RS = 24
We get, 6RS = 24
So, RS = 4
Let RS = x So , QR =3x QS = QR + RS = 4x PQ = QS/2 = 2x PS = 2x + 3x + x = 6x so , 6x=24 x=4
If RS=x then QR=3x thus QS=4x and PQ=2x Now ATQ 4x+2x=24 => x =4..... thus RS=4
PS=24 PQ=1/2 (QS) QR=3RS
QS= QR + RS = 3RS + 1RS = 4RS PQ= 1/2(QS) = 1/2 (4RS) = 2RS PS= PQ + QS = 4RS + 2RS = 6RS 6RS = 24 RS= 4
PS=24( ie PQ+QR+RS=24) given QR=3RS so, PQ+4RS=24 given 2PQ=QS(QS=3RS+RS) so, PQ=2RS 2RS+4RS=24 so RS =4
|PS| = 24; |PQ| = |QS|/2; |QR| = 3|QS|; |RS| = ? (1)
|PQ| + |QR| + |RS| = |PS|; (2)
|QR| + |RS| = |QS|; (3)
|QS|/2 + |QS| = |PS|;
3|QS|/2 = |PS|;
|QS| = 2|PS|/3; (4)
3|RS| + |RS| = |QS| = 2|PS|/3;
4|RS| = 2|PS|/3;
|RS| = |PS|/6 = 24/6 = 4.
PQ+QR+RS = 24 (or) PQ+QS =24
given PQ=0.5 QS...Substitute in above->> 1.5QS = 24.....>>QS=16
QR+RS= QS=16....>> QR=3 RS(Given)...>> 3RS+RS = 16.....>>4RS=16.... SO, RS= 4
Wow all these other answers look complicated, I just did it in my head and got 4.
PS=24.
PS = 24 = PQ + QS = PQ + 2(PQ). 3(PQ) = 24. PQ = 8. QS = 16.
QS = 16 = QR + RS = 3(RS) + RS = 4(RS). RS = 4.
PQ=X, QS=2X, PQ+PS= 3X= 24, so X= 8. So QS=16. QR= 3Z, RS= 1Z, QR+RS= 3Z+Z= 4Z= QS=16, so Z= 4. So RS=4
PQ+QS=24, (QS/2)+QS=24, (3QS/2)=24, QS=16, QR+RS=QS, QR+RS=16, QR+(QR/3)=16, (4QR/3)=16, QR=12, RS =4
PS=24
let X = RS,
3X = QR,
2X = PQ ......(PQ=(QR+QS)/2)
2X+3X+X=24......then simplify
6X=24...divide both sides by 6
X=4
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if PQ=x then QS=2x thus x+2x=24, --> x =8 thus QS=16 now RS=x, QR=3x thus x+3x=16 this implies rs=4