Pokemon- Gotta Catch Em All !!!
Little Pikachu who weighs only , is doing really a good job against Mega Lucario (who is really big in comparison to Pikachu and having a mass of is a dangerous opponent ). After giving a strong thunder bolt which hit Mega Lucario, Pikachu is standing in front of you and waiting for you next order. You order Pikachu to do tackle. Pikachu dashes off. His final velocity on reaching Mega Lucario,(who was first at a distance of from Pikachu), was .How much time did it take Pikachu to reach Mega Lucario? Also , find the force Pikachu applied on Mega Lucario. Give your answer as a sum of the time taken and the force applied in SI units. (Take acceleration due to gravity as [ 9.8 ] and consider that Lucario's Trainer doesn't want to dodge the attack for some secret technique he is about to perform; Consider Pikachu has a constant acceleration)
The answer is 10.75.
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1 solution
Changing every value into SI units we get Mass - 0 . 7 5 0 k g , Distance- 5 0 m Velocity remains the same as it is already in Standard form. By first using the 3rd equation of motion[ v^{2}= u^{2} + 2as ] we find the acceleration to be 1 s 2 m . Then we use the first equation [ v = u +at ] to find the time taken(it comes as 1 0 s e c s )(initial Velocity is 0 as before attacking Pickachu will be standing in front of you). The force can be found from the formula:- F = m a , as we have the mass and found the acceleration above (it is found to be 0 . 7 5 N ) . We add the two values and thus get the asked answer.