Polar coordinates

Calculus Level 2

If the area of the region enclosed by r = 7 cos 3 θ r = 7\cos 3\theta in the interval ( 0 θ 2 π ) i s ( a 2 π b (0\leq \theta \leq 2\pi) is ( \dfrac{a^2 \pi}b ), where a a and b b are positive integers with b b minimized, what is the value of a + b a+b .

10 4 5 11

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Hana Wehbi
May 21, 2016

A = 1 2 A=\frac{1}{2} 0 2 π \int_{0}^{2\pi} ( 7 c o s 3 θ ) 2 d θ (7cos3\theta)^{2} d\theta =

49 2 \frac{49}{2} 0 2 π \int_{0}^{2\pi} 1 + c o s 6 ( θ ) 2 \frac{1+cos6(\theta)}{2} d θ d\theta =

= 49 4 \frac{49}{4} ( θ \theta + sin 6 θ 6 \frac{\sin6\theta}{6} ); θ \theta from 0 2 π 0\to 2\pi

= 49 π 4 \frac{49\pi}{4} ; Thus a 2 = 49 , and b = 4 a + b = 11 a^{2}=49, \text {and} b=4\implies a+b=11

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...