Police And Thief Chase ( Too Confusing )

Algebra Level 1

When the distance between a policeman and a thief is 150 m, the policeman starts chasing the thief. The policeman runs at a speed of 18 m/s and speed of the thief is 12 m/s. If this speed continues, the policeman catches the thief in

15 seconds 25 seconds Can't catch the thief 30 seconds 20 seconds

3 solutions

Andronikus Lumembang
Jan 20, 2015

It means, the policeman has to passed 150 m of distance at a speed of $(18 - 12 = 6 m.s^{-1})$ .

Thus :

$6 = \frac{150}{t}$

$t = 25$ second

Sorry, just realize that it is an algebra problem. Should have write the solution in algebra equation, not in mechanics form. My bad.

Andronikus Lumembang - 6 years, 4 months ago

Ratnadip Kuri
Jan 20, 2015

Let, police will catch the thief after t second.
So, after t second total distance passed by police will be same distance passed by thief and initial distance between police and thief.

that is:

18t = 150+ 12t

6t = 150

so, t= 25 second

Noel Lo
Apr 15, 2015

Hi there, just realised 18 m/s is equal to 64.8 km/h. sounds more like the policeman is Superman hahaah!!!!

Police And Thief Chase ( Too Confusing )

3 solutions

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