What is the sum of the interior angles in a regular 10-gon?
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
I didn't do that in that way but it's good process.....
I think u can use this formula for any one...
n(180-360/n)
when sum of internal angle is asked for any of the regular polygon we can use the formula which is as under, 180 X (n-2)............where n is the number of sides of a polygon, hence, 180 X (10-2)=180 X 8 = 1440
Now keeping in mind that the sum of all angles in a triangle = 180. and rectangle = 360, so the increasing number of sides means adding 180 to it. So, 360 +180 +180+180+180+180+180 = 1440 degrees Bingoo :)
I know the formulae is n -2 * 180 but i find the first method more interesting and conceptual
simply in any one of the Equation Add the value of N After solving the Equation we will get the sum total of internal angles like 180(n-2)= 180( 10-2)=1440 woll be the correct answer.. n is the number of sides.!!!
The total interior angle of a decagon is given by, Total interior angle = (n - 2)180 degrees. So, in a decagon the sum of all interior angle = 1440 degrees. Since the sides are equal, the interior angle at each vertex is = = 144 degrees. For any polygon, the total exterior angle is 360 degrees.
The sum of the interior angles of a triangle = (nx180)-360 = 2160-360 =1440
Using the formula for the sum of the angles in a regular polygon:
( n − 2 ) 1 8 0 = Sum of angles in a polygon
where n is the number of sides...
∴ (10 - 2) * 180 = 8 * 180 = 1440 degrees = 1 4 4 0
It's called a decagon, by the way.
The sum of the internal angles for a polygon of n sides is 1 8 0 ( n − 2 ) . Solving this for n = 1 0 , we find that the sum comes to 1 4 4 0 ∘ .
This is because a polygon of n sides can be split into n − 2 triangles (try it). As the sum of the angles of a triangle is 1 8 0 ∘ , the total sum is simply 1 8 0 m where m is the number of triangles.
(n-2)180 where n is the amount of sides. So: (10-2)(180)=1440
we can find any internal angle of polygon by the formula 180(n-2) where n is no. of sides
for any polygon the sum of the interior angles is 180 (n-2), n being the number of sides. here n is 10 so 180 (10-2) i.e. 180*8=1440
180(n-2) for n sided polygen and it has 10 sides so n=10 then applying the above formulae, 180(10-2) = 180*8 = 1440 answer
did the same way.
there r 10 sides. w.k.t sum of the interior angles is 180(n-2) =>180(10-2) 180(8) 1440
=180(n-2) =180(10-2) =180x8 =1440
Started at 180 for triangle, 360 for quadri, 540 for penta, 720 for hexa, and so on..... thus 180 (n-3 + 1) = 180 (10-3+1) = 180 x 8 = 1,440
Problem Loading...
Note Loading...
Set Loading...
if join all angel with center then 10 triangle will create. Sum of 10 triangle's angles is 180*10=1800, avoid 360 of center then we get 1800-360=1440.