Polygonal Angles 4 – 12-gon Vertex Angles

First, we must find the sum of the interior angles of the shape. This mean we have to use the formula 180(n-2). After we plug in 12 for n, we get a sum of 1800. Now, to find the measure of a vertex angle, we divide by 12 because that is the total number of angles in the 12-gon. Therefore, 150 is the correct answer.

the number of vertices is 12. as it is a 12-gon the interior angle can be find out by 180(n-2) 180(12-2) 180(10) 1800 the vertex angle is given by 1800/12 which is 150

Total exterior angle = 360. ${\text{Each exterior angle}} = \dfrac{360}{12} = 30$ ${\text{Each Vertex angle}} = 180 - 30 = \boxed{150}$

(180(12-2))/(12)

The formula of vertex angle of n-gon 180(n-2)/n n=12 the answer is 150

In a polygon when side is given straight away we can use the formula which is as under 180/n X (n-2)........where n is the number of sides of a polygon, when we substitute the value, we get, 180/12 X (12-2)=15 X 10=150, Hence, 150° is the solution.

sum of interior angles(SIA)=180*(n-2) so SIA=1800 then angle of each vertex=SIA/n-gon=1800/12=150

Hey yo,

as for this problem, given 12 sides polygon, n=12,

the angle of each vertex = (n-2)180 / n = (12-2)180 / 12 = 150 degress....

thanks...

First, we must find the sum of the interior angles of the shape. This mean we have to use the formula 180(n-2). After we plug in 12 for n, we get a sum of 1800. Now, to find the measure of a vertex angle, we divide by 12 because that is the total number of angles in the 12-gon. Therefore, 150 is the correct answer.