Polynomial Problems

Algebra Level 2

The polynomial x 3 + p x 2 x + q x^{3} + px^{2} - x + q has a factor ( x 5 ) (x - 5) and a remainder of 24 when divided by ( x 1 ) (x - 1) .

Find the values of p p and q q .

5 and 1 -5 and -1 6 and -30 -6 and 30

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1 solution

Ahmad Khamis
Aug 2, 2015

let f ( x ) = x 3 p x 2 x + q f(x) = x^{3}-px^{2}-x+q . Since x 5 x-5 is a factor of f ( x ) f(x) , f ( 5 ) = 0 f(5) = 0 . Thus, 125 + 25 p 5 + q = 0 125 + 25p -5 +q =0 which simplifies to 25 p + q = 120 25p + q = -120 . Also, f ( 1 ) = 24 f(1) = 24 because if a polynomial is divided by ( x a ) (x-a) , the remainder is f ( a ) f(a) . Thus, 1 + p 1 + q = 24 1 + p -1 + q = 24 which simplifies to p + q = 24 p+q = 24 . Solving both equations simultaneously yields q = 30 q = 30 and p = 6 p = -6

Moderator note:

Simple standard approach of applying the Remainder-Factor theorem.

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