Let , where the coefficients are integers. If and are both odd, then hich of the following is true
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Suppose p ( k ) = 0 , where k ∈ Z . Then taking everything m o d 2 , we get the either p ( 1 ) ≡ 0 ( m o d 2 ) or p ( 0 ) ≡ 0 ( m o d 2 ) since if k ≡ 0 ( m o d 2 ) ⇒ p ( k ) ≡ p ( 0 ) ( m o d 2 ) . Likewise, if k ≡ 1 ( m o d 2 ) ⇒ p ( k ) ≡ p ( 1 ) ( m o d 2 ) . However, p ( 1 ) ≡ p ( 0 ) = 1 ( m o d 2 ) ⇒ CONTRADICTION. Thus there are no integral roots of p ( x ) .
Q . E . D .