If x − a is a factor of x 3 − 3 x 2 a + 2 a 2 x + b , then find the value of b .
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Good solution.
We can factorise this expression as ( x − a ) 3 + a 2 ( x − a ) + b . This implies x − a is a factor of b which is only possible when b = 0 (since b is independent of x and a)
Won't the second term be negative in the expression above?
f(a) = a³ - 3.a².a + 2.a².a + b = 0 ... ... ... ... => b = 0
Why don't you use latex ?
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Thanks for your suggestion. I also use latex, but only when it is difficult to express the solutions clearly by using symbols.
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As ( x − a ) is the factor, x = a . So, p ( a ) = a 3 − 3 a 3 + 2 a 3 + b = 0 3 a 3 − 3 a 3 + b = 0 b = 0