Poor Larry

Two men, Joe and Larry, are carrying a 24-foot-long board with its weight evenly distributed along its length.

If Joe is at one end and Larry is 6 feet from the other end, what percentage of the weight is Larry carrying?

50% 62.5% 66.7% 75%

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1 solution

Joana Pereira
Jan 31, 2019

So you know that the weight is distributed by Larry and Joe in different ways.The center of mass is at 12f (24f/2) and Larry is applying the force at 6f from the center of mass.

1st step: Calculate the torque (T) choose the regular axis in the center of mass \sum T = 0

TJ + TL + Tg = 0

-12J+6L=0

L=2J

2nd step: Consider the weight (G) (force that the board is applying on the man) 100% and calculate the Force as a percentage: s u m sum F = ma =0

J+L-G= 0

J+ L= G

J+2J=G

3J=100%

J= 33.33%

Joe is carrying 33.33% of the weight

3rd step: Substitute and find the percentage o weight that Larry is carrying: L=2J L=2*33,33% L=66.7%

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