Let x and y be positive integers, with x < y , such that the following equation holds:
2 x y = ( x + 4 ) ( y + 4 )
Find the sum of all possible values of x .
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2 x y = ( x + 4 ) ( y + 4 )
x y = 4 x + 4 y + 1 6
x ( y − 4 ) = 4 ( y + 4 )
x = 4 ( 1 + ( 8 / ( y − 4 ) ) )
y = 2, 3, 5, 6, 8, 12, 20 or 36.
The only possibilities that have x < y are (x = 5, y = 36), (x = 6, y= 20) and (x = 8, y = 12.)
No idea how you made the leap from step3 to step4
In line four, the denominator should be y − 4 , rather than y + 4 .
x = 4 ( 1 + y − 4 8 )
You write (y+4) as (y-4+8). :)
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The equation 2 x y = ( x + 4 ) ( y + 4 ) rearranges to ( x − 4 ) ( y − 4 ) = 3 2 , and the factors of 3 2 so that x − 4 < y − 4 are x − 4 = 1 , x − 4 = 2 , and x − 4 = 4 , which means x = 5 , x = 6 , and x = 8 , and 5 + 6 + 8 = 1 9 .