Possible Functions

Algebra Level 2

Consider the following 6 6 relations on the set of real numbers:

A) y = 2 x 5 y = 2x - 5 ,

B) x 2 + y 2 = 1 x^2 + y^2 =1 ,

C) x = 20 2 y x = 20-\frac{2}{y} ,

D) y = 10 x 2 y = \sqrt{10 - x^2} ,

E) y = 2 x 2 3 x + 4 y = 2x^2-3x+4 and

F) y = x y = |x|

How many of these relations define y y as a function of x x in the domain 10 x 10 -10\leq x \leq 10 ?


The answer is 4.

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1 solution

Arron Kau Staff
May 13, 2014

If y y is a function of x x then there is exactly one value of y y for each x x .

A) y = 2 x 5 y = 2x - 5 : This has one value of y y for all 10 x 10 -10 \leq x \leq 10 .

B) x 2 + y 2 = 1 x^2 + y^2 = 1 : Making y y the subject of the equation, we have y = ± 1 x 2 y = \pm \sqrt{1 - x^2} , thus for x = 0 x = 0 we have y = ± 1 y = \pm 1 . Hence this relation is not a function.

C) x = 20 2 y x = 20 - \frac{2}{y} : Making y y the subject of the equation, we have y = 2 20 x y = \frac {2}{20-x} and this has one value of y y for all 10 x 10 -10 \leq x \leq 10 .

D) y = 10 x 2 y = \sqrt{10 - x^2} : When x > 10 x> \sqrt{10} , y y is not real valued, hence this relation is not a function on the domain 10 x 10 -10 \leq x \leq 10 .

E) y = 2 x 2 3 x + 4 y = 2x^2 - 3x + 4 : This has one value of y y for all 10 x 10 -10 \leq x \leq 10 .

F) y = x y = |x| : This has one value of y y for all 10 x 10 -10 \leq x \leq 10 .

Therefore 4 4 of the 6 6 relations are functions of x x in the domain 10 x 10 -10 \leq x \leq 10 .

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