Consider the following relations on the set of real numbers:
A) ,
B) ,
C) ,
D) ,
E) and
F)
How many of these relations define as a function of in the domain ?
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If y is a function of x then there is exactly one value of y for each x .
A) y = 2 x − 5 : This has one value of y for all − 1 0 ≤ x ≤ 1 0 .
B) x 2 + y 2 = 1 : Making y the subject of the equation, we have y = ± 1 − x 2 , thus for x = 0 we have y = ± 1 . Hence this relation is not a function.
C) x = 2 0 − y 2 : Making y the subject of the equation, we have y = 2 0 − x 2 and this has one value of y for all − 1 0 ≤ x ≤ 1 0 .
D) y = 1 0 − x 2 : When x > 1 0 , y is not real valued, hence this relation is not a function on the domain − 1 0 ≤ x ≤ 1 0 .
E) y = 2 x 2 − 3 x + 4 : This has one value of y for all − 1 0 ≤ x ≤ 1 0 .
F) y = ∣ x ∣ : This has one value of y for all − 1 0 ≤ x ≤ 1 0 .
Therefore 4 of the 6 relations are functions of x in the domain − 1 0 ≤ x ≤ 1 0 .