Possible meals you can get

A restaurant offers 5 choices of appetizer, 10 choices of the main course and 4 choices of dessert. A customer can choose to eat just one course, or two different courses, or all three courses. Assuming that all food choices are available, how many different possible meals does the restaurant offer?

Note: When you eat a course, you only pick one of the choices.


The answer is 329.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

2 solutions

Discussions for this problem are now closed

Ritu Roy
May 8, 2014

A person who eats only an appetizer has 5 choices. A person who eats only a main meal has 10 choices. A person who eats only a dessert has 4 choices.

A person who eats an appetizer and a main meal has 5 × 10 = 50 choices. A person who eats an appetizer and a dessert has 5 × 4 = 20 choices. A person who eats a main meal and a dessert has 10 × 4 = 40 choices.

A person who eats all three courses has 5 × 10 × 4 = 200 choices

So the total number of possible meals = 5 + 10 + 4 + 50 + 20 + 40 + 200 = 329

Here is another way to calculate it:

Including "none" as an option, there are 6 choices of appetizer, 11 choices of main meal and 5 choices of dessert. Thus the total number of choices is 6 × 11 × 5 = 330.

One of these is not a meal though (no appetizer, no main meal and no dessert), so there are 329 possible meals.

The problem is not clear on how many appetizers you can have. The solution makes it clear that it is one.

Star Light - 7 years, 1 month ago
Hatim Zaghloul
May 13, 2014

Given that a customer can choose 0 meal (maximum of two zeros), we can solve the problem in a simple way: 6 x 11 x 5 - 1 = 329. I added one to each course since the choice of 0 exits. I subtracted the case of 0 0 0.

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...