Possible Natural Numbers

How many natural numbers N N are there such that N ! + 10 N! +10 is a perfect square ?


Notation: ! ! is the factorial notation. For example, 8 ! = 1 × 2 × 3 × × 8 8! = 1\times2\times3\times\cdots\times8 .

Infinitely many 1 2 5

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1 solution

Perfect squares are equivalent to either 0 ( m o d 4 ) 0 \pmod{4} or 1 ( m o d 4 ) 1 \pmod{4} .

For N 4 N \ge 4 we have that N ! + 10 2 ( m o d 4 ) N! + 10 \equiv 2 \pmod{4} , so N < 4 N \lt 4 .

Since 1 ! + 10 = 11 , 2 ! + 10 = 12 1! + 10 = 11, 2! + 10 = 12 and 3 ! + 10 = 16 = 4 2 3! + 10 = 16 = 4^{2} , we can conclude that there is only 1 \boxed{1} natural number N N , namely N = 3 N = 3 , such that N ! + 10 N! + 10 is a perfect square.

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