Potential energy in Spring

Classical Mechanics Level 2

Satti stretches a spring 60 cm 60 \text{ cm} from the resting position. The spring’s constant of proportionality is 25 N/m. 25 \text{ N/m.} What is the potential energy of the string?

9 4 J \frac{9}{4} \text{ J} 9 2 J \frac{9}{2} \text{ J} 9 kJ 9 \text{ kJ} 45 kJ 45 \text{ kJ}

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Srinivasa Satti by Srinivasa Satti

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1 solution

just use PE = 1/2 k x^2 , and you will get your answer

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