Power in AM signal

An AM signal has the form u ( t ) = [ 20 + 2 cos 3000 π t + 10 cos 6000 π t ] cos 2 π f c t , u(t) = [20 + 2 \cos{ 3000 \pi t} + 10 \cos{6000 \pi t}]\cos{2 \pi f_{c} t}, where f c = 1 0 5 Hz. f_{c} = 10^{5} \text{ Hz.} Find the power in the side bands.

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