Power of Decimals

Algebra Level 1

1 6 0.25 + 2 5 0.5 {\huge{16^{\color{#D61F06}{ 0.25}} + 25^{\color{#D61F06} {0.5}}}}

Find the value of the expression above.


The answer is 7.

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26 solutions

Parth Lohomi
Feb 25, 2015

Notice that

as x \sqrt{x} is always positive so

1 6 0.25 = 1 6 1 4 = 16 4 = 2 16^{0.25} = 16^{\frac{1}{4}} = \sqrt[4]{16} = 2

and

2 5 0.5 = 2 5 1 2 = 25 2 = 5 25^{0.5} = 25^{\frac{1}{2}} = \sqrt[2]{25} =5

5 + 2 = 7 5+2 = \boxed{7}

upvote if satisfied.

satisfactory explanation

Greg Mallory - 5 years, 6 months ago

Square root of x isn't always positive. It alwqys has 2 solutions, a negative and a positive. Take your 25, for example. Both 5x5 and (-5)x(-5) are 25

Manny Kim - 5 years, 3 months ago

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Wouldn't that be an imaginary number?

Spencer Ingram - 5 years ago

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Aren't all numbers imaginary

Craig P - 5 years ago

Right good comment

Abc Def - 4 years, 4 months ago

√25 only equals 5 not 5 and -5 this is because you can also have a question like this: Find x in the equation below

x^2 = 25 (this equals x = √25)

x^2 - 25 = 0

( x + 5 )( x - 5 ) = 0 (one of the brackets equal to zero)

x1 = - 5 (in first brackets -5 + 5 = 0)

x2 = 5 (in second brackets 5 - 5 = 0)

so x^2 = 25 (or if you want x = √25) has both a positive and negative result whereas√25 by itself only has one positive result.

Also an imaginary number is √-1 (when the number below the square root is negative) because there are no 2 alike numbers when mulitiplied that becomes negative :P

Raboco Loco - 4 years, 12 months ago

nice. ㎡+∑m

zeal 007 - 5 years, 5 months ago

Order of Operations though

Isaac Manuel - 5 years, 5 months ago

But 16^.25 = 4 and 25^.5 =12.5 wtf

Julious Gaitan - 4 years, 12 months ago

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that's what I thought

Holdan Nieves - 4 years, 10 months ago

Even roots have two answers, being a positive and a negative number. Both roots here are even, which means there are 4 possible correct answers, being:

"2+5=7" "-2+5=3" "2+(-5)=-3" "-2+(-5)=-7"

Da Davide - 5 years ago

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Correct - best comment on here.

A Former Brilliant Member - 4 years, 9 months ago

Incorrect. The n th n^{\text{th}} root of a number where n n is an even integer is always positive by the complete definition. If you want to include both positive and negative values, a ± \pm sign is needed before the root, which is not present in the problem.

Zain Majumder - 2 years, 9 months ago

Thank you this app is Sooooooooo good

Honey Rawat - 5 years, 2 months ago

How to write 16 1/4

Abhishek Rana - 5 years ago

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16 = 2^4 So we get 2^(4/4) = 2

Giri Haran - 5 years ago

Yo yo yo ok

anirudh p - 5 years, 5 months ago

...and why do you assume 1/2 here mean to be sign √ ?

Naresh Sharma - 5 years, 5 months ago

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Because 0.5 = 1/2 and √x = x^½ Furthermore: (√x)² = x = (x^½)²

Saif Rehman - 5 years, 4 months ago

Whenever you have a fraction as an exponent, you can change it to a root. All you have to do is take the denominator and move it in front of the root. So for 16^1/4 you would take the 4 and make it the 4th root of 16^1. Then you are able to solve without a calculator. If you were to just punch it in it would give you the answer.

Maddie Hart - 5 years, 3 months ago

I thought powers always had to be whole numbers up to 9?? 😖😣

Dan Jago - 5 years, 4 months ago

So simple, that's why I missed it!

Jonathan Wilkie - 5 years, 1 month ago

how did u solve 16 to the power of one-forth

Christine Elardo - 6 years, 3 months ago

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When you have a number raised to a fractional exponent, such as 1 6 1 4 16^{\frac{1}{4}} above, it can also be written as 1 6 1 4 \sqrt[4]{16^{1}} ; the numerator of the exponent(1) becomes the exponent of the base number(16) and the 4th root of that is taken(4 from the denominator).

Generalization: x n m = x n m x^{\frac{n}{m}}=\sqrt[m]{x^{n}}

In this particular case, we are looking for the 4th root of 16(as illustrated above). This does not require the use of a calculator because most people know 2 4 = 16 2^{4}=16 , so the 4th root is 2. We can prove this by using substitution and the properties of exponents: 1 6 1 4 = ( 2 4 ) 1 4 = 2 ( 4 ) ( 1 4 ) = 2 4 4 = 2 1 = 2 16^{\frac{1}{4}}=(2^{4})^{\frac{1}{4}}=2^{(4)(\frac{1}{4})}=2^{\frac{4}{4}}=2^{1}=\boxed{2}

Natasha Rao - 6 years, 3 months ago

0.25 is the 1/4th of 1.0 hence he has tahen 0.25=1/4

Sid Ughade - 6 years, 3 months ago

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I cant understand it

Abhishek Rana - 5 years ago

Because 2^4=16

anim listowel - 5 years ago
Jade Mijares
Mar 2, 2015

1 6 0.25 = 2 ( 4 ) ( 1 4 ) = 2 16^{0.25} = 2^{(4)(\frac{1}{4})} = 2 2 5 0.5 = 5 ( 2 ) ( 1 2 ) = 5 25^{0.5} = 5^{(2)(\frac{1}{2})} = 5

then: 2 + 5 = 7 2+5 = 7

Just use a powerful calculator

Andrew Zuo - 5 years, 4 months ago
Usman Haider
Mar 1, 2015

16^0.25+25^1/2 =(2^4)^1/4 + (5^2)^1/2 =2+5 =7

I thought 16 to 1/4 power would be 4, and 25 to 1/2 power would be 12.5. Why will half the value of 25 in the problem produce an integer? The answer isn't 16.5?

Jeffrey Kudo - 4 years, 10 months ago

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Me too! That’s what I kept trying.

Sameer Syed - 4 years, 4 months ago
Nick Schot
Jul 22, 2016

Note that: 1 6 0.25 16^{0.25} = 1 6 1 4 16^{\frac {1}{4}} = 16 4 \sqrt[4]{16} = 2 \boxed{2} (Because 2 4 2^4 = 16)

And: 2 5 0.5 25^{0.5} = 2 5 1 2 25^{\frac {1}{2}} = 25 \sqrt{25} = 5 \boxed{5} (Because 5 2 5^2 = 25)

And so you get the sum: 2 + 5 = 7 \boxed{7}

Feyo Vereecken
Jun 14, 2016

I just typed a random number lol

Munem Shahriar
Jun 9, 2017

1 6 0.25 16^{0.25} + 2 5 0.5 25^{0.5}

= 2 + 5

= 7

Nipurn Khatri
Mar 8, 2015

(2^4)^(1/4) + (5^2)^(1/2)

Srijan Singh
May 31, 2021

Epic, 80000 solvers.

Sacha Sergent
Jan 5, 2017

16^0.25= (4^2)^0.25 =4^2•0.25 = 4^0.5 = 2 (0.5 exponent is equivalent to square root) 25^0.5 = 5 (See above) Therefore : 5+2=7

Justin Malme
Jun 2, 2016

1 6 0.25 + 2 5 0.5 = 16^{0.25} + 25^{0.5} =
1 6 1 4 + 2 5 1 2 = 16^\frac{1}{4} + 25^\frac{1}{2} =
8 1 3 + 2 5 1 2 = 8^\frac{1}{3} + 25^\frac{1}{2} =
4 1 2 + 2 5 1 2 = 4^\frac{1}{2} + 25^\frac{1}{2}=
4 + 25 = \sqrt{4} + \sqrt{25} =
2 + 5 = 7 2 + 5 = 7

Sagiv Mor
Jun 2, 2016

16^0.5 = 4^2^0.25 = 4^(2*0.25) = 4^0.5 = 2

25^0.5 = 5^2^0.5 = 5^(2*0.5) = 5^1 = 5

2 + 5 = 7

0Wusu Paul
Apr 14, 2016

=16^1/4 + 25^1/2 =(2^4)^1/4 + (5^ 2)^1/2 =2+5 =7

Benjamin Onweni
Mar 31, 2016

.25=1/4. 16^0.25 = 16^1/4= 2. 0.5 = 1/2. 25^0.5 = 25^1/2 =5 2+5=7.

Tomi Solademi
Mar 22, 2016

16=4^2

(4^2)^0.25 = 4^0.5 = 2

2 + 25^0.5 = 7

Suhas Pr
Mar 8, 2016

16^0.25=2^[4×0.25]=2^1=2

25^0.5=5^[2×0.5]=5

=> 16^0.25 + 25^0.5 = 2+5 = 7 . . . hence the solution

Midori Tu
Jan 16, 2016

Using calculator, we have the correct answer is 7. Satisfactory explanation

Tej Mekako
Jan 8, 2016

Is that all you've got? From Dave Soutar

16^0.25+25^0.5 =(2^4)^0.25 + (5^2)^0.5 = 2^(4 0.25) + 5^(2 0.5) =2^1 + 5^1 =2+5 =7

Chris Taylor
Nov 21, 2015

Many seem to believe that x \sqrt{x} is always positive. This is not true. The square root of x is any number that, when multiplied by itself, gives x. So, the square root of +4 is +/-2. -2 is an equally valid answer to +2.

The reason I came on Brilliant today is that it asked me, on Facebook, to solve 4 9 \sqrt{-4}\sqrt{-9} . Now, x y = x y \sqrt{x}\sqrt{y} = \sqrt{xy} . Hence 4 9 = 36 \sqrt{-4}\sqrt{-9}=\sqrt{36} = +/- 6. So both +6 and -6 are equally valid answers, whereas the answer expected was -6.

Coming back to 1 6 0.25 + 2 5 0.5 16^{0.25} + 25^{0.5}

2 5 0.5 25^{0.5} is easy: +/- 5

1 6 0.25 16^{0.25} is trickier. It is the same as ( + / 4 ) 0.5 (+/-4)^{0.5}

Now 4 \sqrt{-4} involves imaginary numbers. It is +/- 2i

Hence, there are 8 solutions to the original question, all equally valid: 1 6 0.25 + 2 5 0.5 16^{0.25} + 25^{0.5} = ( +/- 2i or +/- 2) +/- 5

Sadasiva Panicker
Oct 22, 2015

16^.25 = 2; and 25^.5= 5; Then 16^.25 + 25^.5 = 2 + 5 = 7

Salman Ather
Oct 16, 2015

81^0.25 + 25^0.5

Amir Hossain
Oct 6, 2015

satisfied ...........

Sayan Roy - 5 years, 6 months ago
Nehemiah Osei
Aug 11, 2015

4^2 is the same as 16, 5^2 is 25

Let 4 be x, then we have (x)^2(0.25) and (x+1)^2(0.5)

The result is x^0.5+(x+1)

0.5 =1/2

Substituting the x we have, 4^1/2+(4+1)

This is the same as √4 +5

Which is 2+5=7

16=2^4 ...0.25=1/4 , 25 = 5^2 ...0.5 =1/2... so 5+2=7

1 6 0.25 + 2 5 0.5 = 1 6 1 4 + 2 5 1 2 = . . . 16^{0.25}+25^{0.5}=16^{\frac{1}{4}}+25^{\frac{1}{2}}=...

. . . = 2 + 5 = 7 ...=2+5=7

Vedang Singh
Feb 28, 2015

We know that 0.25 can be written as 25/100 or,1/4 and 0.5 can be written as1/2. Also,2 raised topower4 is 16 and 5 raised to power2 is 25.So,we get 2^(1/4 4)+5^(1/2 2)=2^(1)+5^(1). I used ^ to denote number raised to power.

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