1 6 0 . 2 5 + 2 5 0 . 5
Find the value of the expression above.
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satisfactory explanation
Square root of x isn't always positive. It alwqys has 2 solutions, a negative and a positive. Take your 25, for example. Both 5x5 and (-5)x(-5) are 25
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Wouldn't that be an imaginary number?
Right good comment
√25 only equals 5 not 5 and -5 this is because you can also have a question like this: Find x in the equation below
x^2 = 25 (this equals x = √25)
x^2 - 25 = 0
( x + 5 )( x - 5 ) = 0 (one of the brackets equal to zero)
x1 = - 5 (in first brackets -5 + 5 = 0)
x2 = 5 (in second brackets 5 - 5 = 0)
so x^2 = 25 (or if you want x = √25) has both a positive and negative result whereas√25 by itself only has one positive result.
Also an imaginary number is √-1 (when the number below the square root is negative) because there are no 2 alike numbers when mulitiplied that becomes negative :P
nice. ㎡+∑m
Order of Operations though
But 16^.25 = 4 and 25^.5 =12.5 wtf
Even roots have two answers, being a positive and a negative number. Both roots here are even, which means there are 4 possible correct answers, being:
"2+5=7" "-2+5=3" "2+(-5)=-3" "-2+(-5)=-7"
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Correct - best comment on here.
Incorrect. The n th root of a number where n is an even integer is always positive by the complete definition. If you want to include both positive and negative values, a ± sign is needed before the root, which is not present in the problem.
Thank you this app is Sooooooooo good
How to write 16 1/4
Yo yo yo ok
...and why do you assume 1/2 here mean to be sign √ ?
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Because 0.5 = 1/2 and √x = x^½ Furthermore: (√x)² = x = (x^½)²
Whenever you have a fraction as an exponent, you can change it to a root. All you have to do is take the denominator and move it in front of the root. So for 16^1/4 you would take the 4 and make it the 4th root of 16^1. Then you are able to solve without a calculator. If you were to just punch it in it would give you the answer.
I thought powers always had to be whole numbers up to 9?? 😖😣
So simple, that's why I missed it!
how did u solve 16 to the power of one-forth
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When you have a number raised to a fractional exponent, such as 1 6 4 1 above, it can also be written as 4 1 6 1 ; the numerator of the exponent(1) becomes the exponent of the base number(16) and the 4th root of that is taken(4 from the denominator).
Generalization: x m n = m x n
In this particular case, we are looking for the 4th root of 16(as illustrated above). This does not require the use of a calculator because most people know 2 4 = 1 6 , so the 4th root is 2. We can prove this by using substitution and the properties of exponents: 1 6 4 1 = ( 2 4 ) 4 1 = 2 ( 4 ) ( 4 1 ) = 2 4 4 = 2 1 = 2
0.25 is the 1/4th of 1.0 hence he has tahen 0.25=1/4
Because 2^4=16
1 6 0 . 2 5 = 2 ( 4 ) ( 4 1 ) = 2 2 5 0 . 5 = 5 ( 2 ) ( 2 1 ) = 5
then: 2 + 5 = 7
Just use a powerful calculator
16^0.25+25^1/2 =(2^4)^1/4 + (5^2)^1/2 =2+5 =7
I thought 16 to 1/4 power would be 4, and 25 to 1/2 power would be 12.5. Why will half the value of 25 in the problem produce an integer? The answer isn't 16.5?
Note that: 1 6 0 . 2 5 = 1 6 4 1 = 4 1 6 = 2 (Because 2 4 = 16)
And: 2 5 0 . 5 = 2 5 2 1 = 2 5 = 5 (Because 5 2 = 25)
And so you get the sum: 2 + 5 = 7
I just typed a random number lol
1 6 0 . 2 5 + 2 5 0 . 5
= 2 + 5
= 7
16^0.25= (4^2)^0.25 =4^2•0.25 = 4^0.5 = 2 (0.5 exponent is equivalent to square root) 25^0.5 = 5 (See above) Therefore : 5+2=7
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16^0.5 = 4^2^0.25 = 4^(2*0.25) = 4^0.5 = 2
25^0.5 = 5^2^0.5 = 5^(2*0.5) = 5^1 = 5
2 + 5 = 7
=16^1/4 + 25^1/2 =(2^4)^1/4 + (5^ 2)^1/2 =2+5 =7
.25=1/4. 16^0.25 = 16^1/4= 2. 0.5 = 1/2. 25^0.5 = 25^1/2 =5 2+5=7.
16=4^2
(4^2)^0.25 = 4^0.5 = 2
2 + 25^0.5 = 7
16^0.25=2^[4×0.25]=2^1=2
25^0.5=5^[2×0.5]=5
=> 16^0.25 + 25^0.5 = 2+5 = 7 . . . hence the solution
Using calculator, we have the correct answer is 7. Satisfactory explanation
Is that all you've got? From Dave Soutar
16^0.25+25^0.5 =(2^4)^0.25 + (5^2)^0.5 = 2^(4 0.25) + 5^(2 0.5) =2^1 + 5^1 =2+5 =7
Many seem to believe that x is always positive. This is not true. The square root of x is any number that, when multiplied by itself, gives x. So, the square root of +4 is +/-2. -2 is an equally valid answer to +2.
The reason I came on Brilliant today is that it asked me, on Facebook, to solve − 4 − 9 . Now, x y = x y . Hence − 4 − 9 = 3 6 = +/- 6. So both +6 and -6 are equally valid answers, whereas the answer expected was -6.
Coming back to 1 6 0 . 2 5 + 2 5 0 . 5
2 5 0 . 5 is easy: +/- 5
1 6 0 . 2 5 is trickier. It is the same as ( + / − 4 ) 0 . 5
Now − 4 involves imaginary numbers. It is +/- 2i
Hence, there are 8 solutions to the original question, all equally valid: 1 6 0 . 2 5 + 2 5 0 . 5 = ( +/- 2i or +/- 2) +/- 5
16^.25 = 2; and 25^.5= 5; Then 16^.25 + 25^.5 = 2 + 5 = 7
satisfied ...........
4^2 is the same as 16, 5^2 is 25
Let 4 be x, then we have (x)^2(0.25) and (x+1)^2(0.5)
The result is x^0.5+(x+1)
0.5 =1/2
Substituting the x we have, 4^1/2+(4+1)
This is the same as √4 +5
Which is 2+5=7
16=2^4 ...0.25=1/4 , 25 = 5^2 ...0.5 =1/2... so 5+2=7
1 6 0 . 2 5 + 2 5 0 . 5 = 1 6 4 1 + 2 5 2 1 = . . .
. . . = 2 + 5 = 7
We know that 0.25 can be written as 25/100 or,1/4 and 0.5 can be written as1/2. Also,2 raised topower4 is 16 and 5 raised to power2 is 25.So,we get 2^(1/4 4)+5^(1/2 2)=2^(1)+5^(1). I used ^ to denote number raised to power.
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Notice that
as x is always positive so
1 6 0 . 2 5 = 1 6 4 1 = 4 1 6 = 2
and
2 5 0 . 5 = 2 5 2 1 = 2 2 5 = 5
5 + 2 = 7
upvote if satisfied.