Power radiated by an electric dipole

The power radiated by an electric dipole of moment $\vec p$ moving with acceleration $\vec w$ is $P=\dfrac{\ddot p^2}{6π\epsilon_0c^3}=\dfrac{p^2\omega^4}{6π\epsilon_0c^3}$ .

Here $\epsilon_0$ is the electric permitivity of free space , $c$ is the speed of light in vacuum, $\omega$ is the angular velocity of the dipole.

Substituting values, we get $P\approx 132.629$ .