Stacking Powers On Powers

Algebra Level 1

[ ( p 0.2 ) 4 ] 3 \large \left[ \left(p^{0.2} \right)^4\right]^3

Simplify the expression above for non-negative p p .

p p p 1.2 p^{1.2} p 2.4 p^{2.4} p 24 p^{24}

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1 solution

Mehul Arora
Feb 20, 2016

By rules of exponents , we have ( p A ) B = p A × B \large (p^A)^B = p^{A\times B} .

Similarly, we can have ( ( p A ) B ) C = p A × B × C \large ((p^A)^B)^C = p^{A\times B \times C} .

In this case, we have A = 0.2 , B = 4 , C = 3 A = 0.2, B = 4, C = 3 , and so the expression simplifies to

p 0.2 × 4 × 3 = p 2.4 \Large p^{0.2\times 4\times3} = p^{2.4} \qquad \square


Note that p A B C p A × B × C p^{A^{B^C}} \ne p^{A\times B \times C} . You may read further in this wiki: How are exponent towers evaluated? Is a b c a^{b^c} equal to a b × c a^{b\times c} ? .

Same method

Aatreya Hui - 5 years, 3 months ago

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