There are n n resistors of the same resistance which are first connected in parallel and then in series. Find the ratio of power consumed by the resistors when in parallel to when they're in series.

n^2 cannot be determined 1/n 1/n^2

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1 solution

In case of the parallel combination, the total resistance of the circuit is R n \frac {R}{n} . In case of the series combination, the total resistance of the circuit is n R nR . Remember, p o w e r = V 2 t o t a l r e s i s t a n c e power=\frac {V^2}{total resistance} . If we take the ratios, answer is n 2 n^2

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