Powers galore!

Algebra Level 3

Find all triples of positive integers ( x , y , z ) (x, y, z) satisfying 1 + 2 x 3 y = z 2 1+2^{x}3^{y}=z^{2} .

Insert your answer as the sum of all possible values of z z .


The answer is 29.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

X X
Aug 9, 2018

2 x 3 y = ( z + 1 ) ( z 1 ) 2^x3^y=(z+1)(z-1) , z + 1 z+1 and z 1 z-1 have to be even numbers,so let z 1 = 2 a , z + 1 = 2 b , x 2 = x z-1=2a,z+1=2b,x-2=x' .

2 x 3 y = a b 2^{x'}3^y=ab ,so one of a a or b b has to be a power of 2 2 ,and the other has to be a power of 3 3 .

Because of Mihailescu's theorem , ( a , b ) = ( 2 , 3 ) , ( 3 , 4 ) , ( 8 , 9 ) (a,b)=(2,3),(3,4),(8,9)

z = 5 , 7 , 17 z=5,7,17

You could quote Mihailescu's theorem to show that these are the only possible values for a a and b b

Freddie Hand - 2 years, 10 months ago

Log in to reply

Thanks.I've editted it.

X X - 2 years, 10 months ago

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...