Find all triples of positive integers satisfying .
Insert your answer as the sum of all possible values of .
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2 x 3 y = ( z + 1 ) ( z − 1 ) , z + 1 and z − 1 have to be even numbers,so let z − 1 = 2 a , z + 1 = 2 b , x − 2 = x ′ .
2 x ′ 3 y = a b ,so one of a or b has to be a power of 2 ,and the other has to be a power of 3 .
Because of Mihailescu's theorem , ( a , b ) = ( 2 , 3 ) , ( 3 , 4 ) , ( 8 , 9 )
z = 5 , 7 , 1 7