When writing out some powers of 2, we begin to notice something. 2 0 = 1 2 1 0 = 1 0 2 4 2 2 0 = 1 0 4 8 5 7 6 2 3 0 = 1 0 7 3 7 4 1 8 2 4 It seems that the first digit of the answer when raising 2 to a multiple of 10 is always a 1.
What is the smallest multiple of 10 which can be the exponent of 2 such that the leading digit of the result is not a 1? If you think that there is no such number, enter -1 as your answer.
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Yes, making it 1.024 is the key to solving it
As I understand it, these types of problems only became "exotic" as students started using calculators instead of slide rules to write numbers in scientific notation.
Either way, nice solution.
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One of my worries about creating the problem was that people would just try it on a calculator until they found 290 and 300 rather than using the log method. But then again, only 9 out of 18 attempts have been right at the time of writing
Excellent solution
@Michael Mendrin Sir, same way!!!! Just a minor typo in the end........the value of n should be the reciprocal of what you have written........!!!
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2 1 0 n = ( 2 1 0 ) n = 1 0 2 4 n = ( 1 . 0 2 4 ) n ⋅ 1 0 3 n
Since 1 0 3 n does not affect the 1st digit, we look for what value of n such that ( 1 . 0 2 4 ) n > 2
n L o g ( 1 . 0 2 4 ) > L o g ( 2 ) , so we first solve
n = L o g ( 1 . 0 2 4 ) L o g ( 2 ) ≈ 2 9 . 2 2 6 3 . . , so the answer is 1 0 n = 3 0 0 , that is, 2 3 0 0 starts with 2